A 0.91 L of a solution of 2.0 M HCI can be prepared with what?

Explanation:

HCl can be obtained with different concentrations of HCL in water.

If for example, you purchased 37.2% HCL it would have a density of 1.2 g/mL. The molecular weight of HCl is 36.46 g/mole

1.2g/mL x 1000 ml/L = 1200 g/L = 1200g/L x 0.372 =(446.4g HCl/L)/36.46 g/mole = 12.2 M/L HCl

To prepare a 2M solution:

V1 = ?, M1 = 12.2M

V2 = 1L, M2 = 2M

V1*M1=V2*M2

V1 = (V2*M2)/M1

V1 = 1*2/12.2 = 0.164 L or 164 mL of 12.2M HCl diluted to 1 Liter with water will yield a 2M solution.

HÖPÊ ŸÖÛ ŤHÄŤ ÏŠ HĘŁP FŪŁŁ

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.