Consider the following series of balanced chemical reactions in the production of potassium bicarbonate, KHCO3:
K2SO4 + 4C > K2S +4 CO
K2S + CaCO3 > Gas + K2CO3
K2CO3 + H2b + CO2 > 2 KHCO3
If potassium sulfate, K2SO4, is the limiting reactant, how many grams of KHCO3 can be
produced from 45.00 g of K2SO4?

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2

може ли да зареждате повече информация, моля