14. A gas in a 400 ml flask exerts pressure of 81.0 kPa at 25.0°C. If the gas was in a 250 ml container at a pressure of 101 kPa, the temperature would be
a) - 124 °C
b) - 41.2°C
c) 20.0°C
d) 232 °C

B would be the correct answer

Explanation: You will need to use P1V1/T1=P2V2/T2

So

P1= 81.0kPa /101 =0.799atm

V1=0.4L

T1=25.0C +273.15K= 298.15K

P2= 101kPa /101 = 1atm

V2=0.25L

T2= ?

T2=P2V2T1/P1V1

(1.0atm)(0.25L)(298.15K)/(0.799atm)(0.4L) =233.22K-273.15=-39.92C

if you're asking what comes out, it's steam.

hi my dude or dudette