Chemistry, 18.10.2021 19:20 shorty178658

Vrite the formula equation and net ionic equation for each reaction.
H3PO4(aq) + NaOH(aq)

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Answer from: lacourboud20005

formula equation:

3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)

ionic equation:

H+(aq)+OH−(aq)→H2O(l)H+(aq)+OH−(aq)→H2O(l).

Explanation:

1. Balance the equation

2. Write state symbols

3. Split the aqueous compounds to its ions. DO NOT SPLIT THE COMPOUNDS WHICH ARE NOT AQUEOUS

4. Cut the spectator ions from products and reactants side.

5. Write the remaining stuff as it is WITH state symbols..

3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)

3Na+(aq) 3OH-(aq) + 3H+(aq) PO4-3(aq)→ 3Na+(aq) PO4-3(aq) +3H2O(l)

(cut spectator ions and write the stuff that remains)

3H+(aq) + 3OH-(aq) → 3H2O(l)

BUT SINCE WE CAN SIMPLIFY THE EQUATION BY CUTTING ALL THE THREES IT BECOMES..

H+(aq) + OH-(aq) → H2O(l)

BTW IN EVERY NEUTRALIZATION REACTION IT HAS THE SAME IONIC EQUATION WHICH IS :

H+(aq) + OH-(aq) → H2O(l)

Answer from: Quest

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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Vrite the formula equation and net ionic equation for each reaction.
H3PO4(aq) + NaOH(aq)...

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