Oxygen is a product of the decomposition of mercury(II) oxide as shown below. 2 HgO(s) → 2 Hg(ℓ) + O₂(g)

You have determined that 9.46 × 10⁻³ moles of O₂(g) were produced in this reaction. What volume (in L) of O₂ will be produced from the decomposition of 4.10 g of HgO assuming a pressure of 1.50 atm and a temperature of 122.0°C?

Remember the gas constant, R, is 0.08206 L･atm/mol･K.

alkali metals:  hydrogen (H), lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).  These are (except for hydrogen) soft, shiny, low-melting, highly reactive metals, which tarnish when exposed to air.  The name comes from the fact that when these metals or their oxides are dissolved in water

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j