Calculate ΔH for the following reaction: PCl3 (l) + Cl2 (g) → PCl5 (s)

given the following:

1) 2 P (s) + 3 Cl2 (g) → 2 PCl3 (l) ΔH = -639.4 kJ

2) 2 P (s) + 5 Cl2 (g) → 2 PCl5 (s) ΔH = -887.0 kJ

The following questions a24 - a26 relate to 100 ml of 0.0150 m solution of benzoic acid (c6h3cooh). ka(c6h3cooh) = 6.4 x 10^-5. what is the ph of the solution after the addition of 1 x 10^-3 moles of naoh? you may assume no volume change to the solution upon addition of the naoh.