A pure titanium cube has an edge length of 2.63 in. How many titanium atoms does it contain? Titanium has a density of 4.50g/cm3. I messed something up along the line and would appreciate it if someone could tell me what I did wrong and how to solve it correctly. V = 2.63^3 = 18.19in^3
1in^3 = 16.387cm^3
18.19/16.387 = 1.1539
Density = 4.50g/cm^3
1.1539 * 4.50 = 5.1926
1mol Ti = g/47.867
5.1926/47.867 = 0.108479
1mol = 6.02 * 10^23atoms
0.108479/(6.02 * 10^23) = 6.53 * 10^22

This is wrong. Why!?

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied