After developing your hypothesis, the next step in the inquiry process is to design a controlled experiment in order to test your hypothesis. in a controlled experiment, all variables are kept constant except the one that you are testing. the variables you keep the same are called controlled variables. the variable that you change or test is called the manipulated variable. the variable that responds to changes you make is called the responding variable. a. how would you design a controlled experiment to test the hypothesis you made about the volume of a gas? b. what is the manipulated variable in your experiment? c. what is the responding variable in your experiment?

For your experiment, you would need to see decide what your hypothesis is before you design the experiment. If you want to see if the volume of gas changes depending on the container it's in, then you need to set it up depending on what you want to do with the volume.
The manipulated variable would be whatever you change, so if you switch container sizes, that would be the manipulated variable and the responding variable would be the volume of the gas.

I hope this helps!

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.