Calculate the following quantity: volume in milliliters of 6.67 x 10-2 M adenosine triphosphate (ATP) that contains 8.31 mmol of ATP.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

c) should be the answer.

i believe the answer is 5,000