What mass of carbon monoxide is needed to react with 480kg of iron oxide

Explanation:

First off, you need to find the number of moles of iron oxide (Fe2O3) present in 480kg. The equation is mol = mass (g) / Mr

- you're given the mass of Fe2O3 in kg, so just need to covert to g; = 480 x 1000 = 480,000g

- Mr of Fe2O3 is found by adding all relative atomic masses from the Periodic Table;

2 x Fe = 2 x 56 = 112

3 x O = 3 x 16 = 48, therefore Mr of Fe2O3 = 112 + 48 = 160

- now divide the mass by the Mr to find mol Fe2O3 = 480,000 / 160 = 3000 mol

You know from the equation that 3 x CO reacts with Fe2O3, so you multiply number of Fe2O3 mol x 3 = 9000 mol

Now you need to find mass of CO; based on the formula mol = mass (g) / Mr, you can rearrange this to make mass the subject; mass (g) = mol x Mr

Mr of CO = 12 + 16 = 28

Therefore mass CO (g) = 9000 x 28 = 252,000g (or 252kg).