using the periodic table which of the following is the correct electron configuration of vanadium in its ground state?

Explanation:

The ground state electron configuration of ground state gaseous neutral vanadium is [Ar]. 3d3. 4s2 and the term symbol is 4F3/2.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer