2. Consider the following equation and rate study: 4HI () + 02.) → 21269) +2H206)
HI) mol/L
O2m) mol/L
Rate (mol/L. s)
0.010
0.010
0.020
0.010
0.020
0.020
4.2 x 10-3
8.4 x 10-3
1.68 x 10-2
a) Write the rate law equation for this reaction (show your work). (2 mark)
b) Calculate the k value. (2 marks)
c) Propose a reaction mechanism. Recall - an intermediate becomes the reactan
the next step of the mechanism.

answer; i believe that the correct answer is (a) potassium(k)

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"