How many kilowatt-hours of energy are necessary to heat the air in the house from 9 ∘C to 27 ∘C? The heat capacity of air is 1.03 J/g∘C.

The amount of air (in grams) is required for an answer. The process is outlined below.

Explanation:

An example for 1 kg of air:

Energy = (specific heat)*(mass)*(temperature change)

Joules = (1.03J/g°C)*(1,000g)*(27°C - 9°C)

Joules = 18540J

Coversion: 1 Joule = 2.78E-07 kwh

Kwh to heat 1 kg of air from 9 to 27°C is 5.15E-03 kwh

Use the same process with the actual mass of air in the house. If you are given house dimensions, calculate the volume and multiply by the density of air to get grams air. (Remember to subtract the volume taken up by household items (e.g., beer cans).

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

i would say b

explanation:

but i think i would need more information than that