Chlorine has an atomic mass of 35.543 and two naturally occurring isotopes. Isotope A has a relative mass of 34.96885 and an abundance of 75.53%. What is the mass and abundance of the second isotope?

Knowing that the two naturally occurring isotopes make up the molar mass of chlorine wholly
Therefore, we can deduce that the natural abundance of another isotope would be 24.47% (1 - 75.53%)

Let x be the mass number of another isotope

Using the equation:
Relative isotopic mass x relative abundance + …… = relative atomic mass, we get:

x(24.47%) + 34.96885(75.53%) = 35.543
x = 37.31519

Therefore, the relative isotopic mass of another isotope is 37.31519 and its abundance is 24.47%

Hi + naoh -> h2o + nal

Answer(28.02g/mol);