Part B Calculate the specific heat (J/g °C) for a 25.0 g sample of a metal that absorbs 685 J when temperature increases from 33.4°C to96.8 °C.

the answer is the first option

explanation:

just googled it m8. not that hard

lol

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.