At 1000 °C, K = 0.403 for the following reaction: FeO(s) + CO(g) = Fe(s) + CO2(g) An excess amount of FeO is reacted with 5.0 bar of CO(g) at 1000 °C. Calculate the partial pressure (in bar) of CO(g) present at equilibrium. Due to limitations of CCLE, report your answer in standard format (e. g. 432 instead of 4.32 x 102). Enter only your numerical answer without units.

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a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

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