The gas phase decomposition of sulfuryl chloride 600 K SO 2 Cl 2 (g) SO 2 (g)+Cl 2 (g) is first order in S*O_{2} * C * l_{2} a rate constant of 0.00280 min If the initial concentration of S*O_{2} * C * l_{2} is 0.00379 Mthe concentration of S*O_{2} * C * l_{2} will be 0.000819 M after

the answer is

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j