Be sure to answer all parts. The species CO, CN−, and C22− are isoelectronic. Determine the MO diagrams (assume 2s−2p mixing, as in N2), and determine the bond order that the species share. (σ2s)2(σ2s)2(π2p)2(π*2p)2(σ*2p)2 (σ2s)2(σ*2s)2(π2p)2(π2p)2(σ*2p)2 (σ2s)2(σ2s)2(π2p)2(π*2p)2(σ2p)2 (σ2s)2(σ*2s)2(π2p)2(π2p)2(σ2p)2 (σ2s)2(σ*2s)2(π2p)2(π*2p)2(σ2p)2 Bond order =

You just calculated that the heat of fusion for chloromethane is 6400 j/mol. the heat of fusion for hydrogen is 120 j/mol.? which of the following account for this difference? more than one correcta. chloromethane can absorb more energy at the same temperature. b. hydrogen has stronger intermolecular forces than chloromethane. c. hydrogen molecules can pack more closely than chloromethane molecules. d. chloromethane experiences dipole-dipole interactions. e. chloromethane has a higher molar mass than hydrogen.