Compound A has molecular formula C7H140 and reacts with sodium borohydride in methanol to form an alcohol. The 1H NMR spectrum of compound A exhibits only two signals: a doublet (I12) and a septet (2). Treating compound A with 1,2-ethanedithiol (HSCH2CH2SH) followed by Raney nickel gives compound B. (a) How many signals will appear in the 1H NMR spectrum of compound B?
(b) How many signals will appear in the 13c NMR spectrum of compound B?
(c) Complete the description of how you could use IR spectroscopy to verify the conversion of compound A to compound B. Compound A is a 1, while compound B is an. Therefore, Compound A exhibit a signal at approximately 1715 cm, while compound B exhibit a signal in the same region.