During a nuclear reaction, an unknown particle is absorbed by a copper 6329Cu2963Cu nucleus, and the reaction products are 6229Cu2962Cu, a neutron, and a proton. What is the nucleon number of the nucleus formed when the 6329Cu2963Cu nucleus absorbs the unknown particle

i'm not sure

explanation:

i'll try whatever you got

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

c. 75.7

i think that is the right