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Chemistry, 03.08.2021 06:40 cindykulei3719

hòa tan hoàn toàn hỗn hợp gồm Fe, FeO, Fe2O3, Fe(OH)2 và Fe(OH)3 trong dung dịch chứa 0,26 mol H2SO4 và 0,22 mol HNO3, thu được dung dịch X (chỉ gồm muối) và 0,05 mol khí NO (sản phẩm khử duy nhất). Cho HCl dư vào dung dịch X lại thấy có 0,01 mol NO thoát ra. Tính khối lượng muối khan X.​

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hòa tan hoàn toàn hỗn hợp gồm Fe, FeO, Fe2O3, Fe(OH)2 và Fe(OH)3 trong dung dịch chứa 0,26 mol H2SO4...
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