For the following reaction of N2O4, the equilibrium constant is 0.593 at a particular temperature. N2O4(g) ⇌ 2 NO2(g)
If the initial concentration of N2O4 is 0.880M, what are the equilibrium concentrations?

Please show work!

"0.583" is the appropriate answer.

Explanation:

Let,

The initial constant of be "C".

Amount of dissociated into be "x".

now,

Initial constant               C            -

Equilibrium constant     C          2x

The Kc is given as:

⇒

hence,

The constant of will be:

=

=

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