22.4l of ammonia is reaxts with 1.406 mole of oxygen to produce NO and h2o .1.what volume of no is produced at ntp​

The volume of NO is 22.4L at STP

Explanation:

Based on the reaction:

2NH3 + 5/2O2 → 2NO + 3H2O

2 moles of NH3 react with 5/2 moles of O2 to produce 2 moles of NO.

To solve this question, we need to find the moles of each reactant in order to find the limiting reactant as follows:

Moles NH3 -Molar mass: -17.01g/mol-

Using PV = nRT

PV/RT = n

Where P is pressure = 1atm at STP

V is volume = 22.4L

R is gas constant = 0.082atmL/molK

T is absolute temperature = 273.15K

1atm*22.4L/0.082atmL/molK*273.15K = n

n = 1.00 moles of NH3

For a complete reaction of 1.00 moles of NH3 are needed:

1.00 moles NH3 * (5/2moles O2 / 2moles NH3) = 1.25 moles of O2

As there are 1.406 moles of O2, the limiting reactant is NH3

The moles of NO produced are the same than moles of NH3 because 2 moles of NH3 produce 2 moles of NO. The moles of NO are 1.00 moles

And as 1.00moles of gas are 22.4L at STP:

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