Find the number of moles of sodium hydroxide in 25cm3 solution of concentration 0,1 mol/dm3​

0.0025  moles

Explanation:

25cm^3 = 25/1000 dm^3

Conc = mol/dm^3

Mol = conc * dm^3

Mol = 0.1 * 25/1000

c. orbital shape i hope this is correct

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally