What amount of SeC16 is needed to produce 4.45 mol of chlorine gas in the reaction Seclo +0 218) —SeO, +3Cl2te)?
2.85 mol
0.95 mol
5.70 mol
8.55 mol
1.49 mol

1.48 moles of SeCl6 are needed

Explanation:

Based on the reaction:

SeCl6 + O2 → SeO2 + 3Cl2

1 mole of SeCl6 reacts producing 3 moles of Cl2.

To solve this question we need to use the conversion factor:

1mol SeCl6 = 3mol Cl2

As we want to produce 4.45 moles of Cl2, we need:

4.45 mol Cl2 * (1mol SeCl6 / 3mol Cl2) =

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.

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