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Aluminum reacts with chlorine gas according to the following equation:
2Al(s) + 3Cl2(8)—2A1C13(s)
(a) What is the mole ratio of Cl2 to Al?
(b) How many moles of Cl2 are required to react with each mole of Al?
(c) How many moles of Cl2 are required to react with 0.085 mol of Al?
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You know the right answer?
Aluminum reacts with chlorine gas according to the following equation:
2Al(s) + 3Cl2(8)—2A1C13(s)
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