An ideal gas has a temperature of 25 oC, a pressure of 1.7 atm, and volume of 345 mL, how many moles of gas are present in the container?

There are 0.024 moles of gas are present in the container.

Explanation:

Given: Temperature = = (25 + 273) K = 298 K

Pressure = 1.7 atm

Volume = 345 mL (1 mL = 0.001 L) = 0.345 L

Formula used is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T= temperature

Substitute the values into above formula as follows.

Thus, we can conclude that there are 0.024 moles of gas are present in the container.

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