PLS HELP I WILL REWARD MOST BRAINLIEST You are in a lab and you use 57.50 g of Na(s) to react with Cl(g). Below is the reaction that happens from this.

Na + Cl2 → NaCl

Your percent yield is 95%. From this info what is the actual yield?

Actual yield = 138.94 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Na + Cl₂ —> 2NaCl

Next, we shall determine the mass of Na that reacted and the mass of NaCl produced from the balanced equation. This can be obtained as follow:

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of NaCl = 23 + 35.5

= 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g

SUMMARY:

From the balanced equation above,

46 gof Na reacted to produce 117 g of NaCl.

Next, we shall determine the theoretical yield NaCl. This can be obtained as follow:

From the balanced equation above,

46 gof Na reacted to produce 117 g of NaCl.

Therefore, 57.50 g of Na will react to produce = (57.50 × 117)/46 = 146.25 g of NaCl.

Thus, the theoretical yield of NaCl is 146.25 g

Finally, we shall determine the actual yield of NaCl. This can be obtained as follow:

Percentage yield = 95%

Theoretical yield = 146.25 g

Actual yield =?

Percentage yield = Actual yield / Theoretical yield × 100

95% = Actual yield / 146.25

Cross multiply

Actual yield = 95% × 146.25

Actual yield = 95/100 × 146.25

Actual yield = 0.95 × 146.25

Actual yield = 138.94 g

it means there are 3 atoms of oxygen