What is the balanced equation for the redox reaction between copper and sulfuric acid that forms copper(II)sulfate, sulfur dioxide, and water?
A. Cu + 2H+ + 25042- → Cu2+ + S0 2+ + SO2 + H2O + 2H+
B. Cu + 4H+ + 25042- → Cu2+ + SO42+ + SO2 + 2H20
C. Cu + 4H+ + 25042 → Cu2+ + S022+ + SO2 + 2H2O + 2e
D. Cu + 2H+ + 25042- + 2e → Cu2+ + SO42+ + SO2 + H2O

The answer to the question is d

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.