600cm3 gas nitrogen bertindak balas dengan 600cm3 gas nitrogen pada keadaan bilik. Tentukan bahan tindak balas yang manakah digunakan secara berlebihan. Hitung isipadu maksimum ammonia yang terhasil daripada tindak balas ini. [1 mol gas ammonia memenuhi 24dm3 pada keadaan bilik]

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

i think it is true since you can test the answer and can use observations to complete it.

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.