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Chemistry, 12.07.2021 17:00 raptortrainor2013

5 – (PUC-PR) Uma célula galvânica é constituída de 2 eletrodos: 1º eletrodo: 1 lâmina de ferro metálico submersa numa solução de FeSO4 1M. 2º eletrodo: 1 lâmina de prata metálica submersa numa solução de AgNO3 1M. Sabendo-se que os potenciais normais de redução desses dois elementos são: Fe+2 + 2e-→ Fe E0 = - 0,44 V Ag+ + 1e- → Ag E0 = + 0,80 V88 O potencial dessa célula, quando os dois eletrodos são ligados entre si internamente por uma ponte salina e externamente por um fio de platina, será: a) + 0,36 V. b) - 0,36 V. c) - 1,24 V. d) - 1,36 V. e) + 1,24 V.

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