Ethylene glycol (antifreeze) has a density of 1.11 g/cm^3. What is the volume (in m^3) of 9.7 tons?(1 ton = 2.000*10^3lb; 1 kg= 2.2046 lb

The volume of 9.7 tons of given ethylene glycol is 0.0079 .

Explanation:

Given: Density = 1.11

Mass = 9.7 tons

Convert tons into lb as follows.

Now, lb is converted into kg as follows.

1 kg = 1000 g

So, 8.79 kg = 8790 g

Density is the mass of a substance divided by its volume. Hence, volume of ethylene glycol is calculated as follows.

Thus, we can conclude that the volume of 9.7 tons of given ethylene glycol is 0.0079 .

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