I. En un laboratorio se hizo reaccionar una disolución de ácido sulfúrico (H2SO4) con otra de hidróxido de sodio (NaOH), ambos acuosos. Para formar sulfato de sodio (Na2SO4) y 2 moléculas de agua (H2O) líquido. Completa en relación con la ecuación química que representa la reacción:

In a laboratory, a solution of sulfuric acid (H2SO4) was reacted with another of sodium hydroxide (NaOH), both aqueous. To form sodium sulfate (Na2SO4) and 2 molecules of liquid water (H2O). Complete in relation to the chemical equation that represents the reaction:

Explanation:

The balanced chemical equation of the reaction is:

Thus, one mole of sulfuric acid reacts with two moles of sodium hydroxide.

oh it is true if thats what you are asking

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml