Use a periodic table to write the electron configuration of selenium

The electronic configuration of selenium is

Explanation:

The atomic number is defined as the number of protons or number of electrons present in a neutral atom.

Number of electrons will be equal to the atomic number of an atom.

Electronic configuration is defined as the representation of electrons in an atom.

Selenium is the 34th element of the periodic table.

The electronic configuration of Selenium is

It has 6 electrons that are present in the outermost shell.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

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