PLEASE ITS FOR MY FINAL How would you go about calculating the molarity of the following solution: 19.5 grams of Be(OH)2 is dissolved in enough water to make a 1.5 L solution.

0.302M

Explanation:

Molarity, which is the molar concentration of a solution can be calculated as follows:

Molarity = number of moles (n) ÷ volume (V)

According to this question, 19.5 grams of Be(OH)2 is dissolved in enough water to make a 1.5 L solution.

Using mole = mass/molar mass to calculate the number of moles in 19.5g of Be(OH)2

Molar mass of Be(OH)2 = 9 + (16 + 1)2

= 9 + (17)2

= 9 + 34

= 43g/mol

mole = 19.5/43

mole = 0.453moles

Molarity = n/V

Molarity = 0.453/1.5

Molarity = 0.302M

the correct answer is boyle