Increasing the molality of a solution the boiling point of a solution. Changing the solute to one that creates fewer dissolved species the boiling point of the solution compared to the original solution. Starting a solution at a warmer temperature the boiling point of a solution.

-Increase the boiling point

-Decrease the boiling point

- Will not change

Explanation:

The boiling point of a solution is the temperature at which its vapor pressure equals the external atmospheric pressure.

Because the presence of a nonvolatile solute lowers the vapor pressure of a solution, it also affects the boiling point of the solution. Remember that molality is a concentration unit that is obtained by dividing the moles of solute in one kilogram of solvent. Increasing the molality, that is, increasing the amount of solute in a solution, will increase the boiling point of a solution. This is an example of a colligative property, a property that depends only on the number of solute particles in solution and not on the nature of the solute particles. Because of this same reason, changing the solute to one that creates fewer dissolved species, which are the ones that will exert their effects in the solution, will decrease the boiling point compared to the original solution, since here there are fewer particles in solution.

Since the definition of boiling point states that it is a temperature at which vapor pressures are equal, starting a solution at a warmer temperature will not change the boiling point, it will just take less time to reach that same boiling point.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.