An evaporuter system concentraing a weak liquor from 5% to 50% Solids handls 100kg of solid per hour. if the same is to concentrate a weak liquor from 4% to 35%, find the capacity of the system in term of solids that can be handlied Per hour assuming water evaporatin to be same in both the eases

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

put the answers   and i could answer.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally