You observed the formation of several precipitates in the Reactions in Solution lab exercise. Identify the precipitate in each of the following reactions: a. The yellow precipitate formed in the reaction between KI and Pb(NO3)2 is . b. The white precipitate formed in the reaction between BaCl2 and H2SO4 is . c. The brown precipitate formed in the reaction between NaOH and FeCl3 is . d. The blue precipitate formed in the reaction between CuSO4 and NaOH is .

See explanation

Explanation:

a) the reaction between KI and Pb(NO3)2 occurs as follows;

2KI(aq) + Pb(NO3)2(aq) ---> PbI2(s) + 2KNO3

Hence the yellow precipitate in the reaction is PbI2

b) the reaction between BaCl2 and H2SO4 occurs as follows;

BaCl2(aq) + H2SO4(aq) ---> BaSO4(s) + 2HCl(aq)

Hence the white precipitate in the reaction is BaSO4

c) the reaction between NaOH and FeCl3 is as follows;

3NaOH(aq) + FeCl3(aq) > Fe(OH)3 + 3NaCl(aq)

Hence the brown precipitate is Fe(OH)3

d) the reaction between CuSO4 and NaOH occurs as follows;

CuSO4(aq) + 2NaOH(aq) ---> Cu(OH)2(s) + Na2SO4(aq)

Hence the blue precipitate is Cu(OH)2

it is stable as it is in group 0 which have full outer shells of electrons