Un corredor se desplaza por un camino rectilianeo, de tal forma que paso por los puntos a, b, c, d. Entre cada punto hay 150m. a. Si recorre de punto A al D ¿cuento es su desplazamiento?. b. Si va del punto A al D y regresa al punto C ¿cual fue su distancia y desplazamiento? c. Si recorre de A hasta D y vuelve a A ¿cual es su distancia y desplazamiento?

the correct answer would be d. hope this !

explanation:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2