an experiment is carried out to determine the formula of an oxide of mercury. the oxide is a red solid. it decomposed into its elements when heated at room temperature and pressure (r. t.p.). // mass of oxide of mercury: 2.16g // volume of oxygen collected at r. t.p.: 120cm³ // what is the mass of mercury produced?

Mass of mercury produced = 2.00 g

Explanation:

At room temperature and pressure, the temperature T = 25° C or 298.15 K while the pressure = 1 atmosphere or 760 mmHg.

Mass of oxide of mercury decomposed at room temperature and pressure = 2.16 g

Volume of oxygen produced = 120 cm³ or 0.12 dm³

One mole of any gas has a volume of 24 dm³ at room temperature and pressure.

Therefore, number of moles of oxygen produced = 0.12 dm³ / 24 dm³/mol = 0.005 moles

Mass of oxygen produced = number of moles × molar mass

Molar mass of oxygen = 32 g/mol

Mass of oxygen produced = 0.005 moles × 32 g/mol = 0.16 g

Thus, mass of mercury produced = mass of mercury oxide decomposed - mass of oxygen produced

Mass of mercury produced = 2.16 g - 0.16 g

Mass of mercury produced = 2.00 g

well off of my head we know that the perfume bottle is most likely opened, or broken. i can also tell it is moving at low and high concentration because it is covering the other side of the room. what we can obtain from this information is it explains why the odor can be detected at the other side of the room.

the answer is 303.15 or 303