A 6.00 g sample of an optically pure compound was dissolved in 40.0 mL of CCl4. The observed rotation was +3.30 °, measured in a 10.0 cm (1.00 dm) polarimeter tube.

The question is incomplete, the complete question is:

If a 6.00 g sample of an optically pure compound was dissolved in 40.0 mL of and the observed rotation was +3.30°, measured in a 10.0 cm (1.00 dm) polarimeter tube, how would one determine the specific rotation of the pure compound?

The specific rotation of the pure compound is

Explanation:

To calculate the specific rotation of a pure compound, we use the equation:

where,

= specific rotation of a pure compound

= observed rotation of the compound = [ex]+3.30^o[/tex]

C = concentration in g/mL = 6.00 g/40 mL = 0.15 g/mL

l = path length = 1.00 dm

Putting values in above equation, we get:

Hence, the specific rotation of the pure compound is

the answer is definitely c.

there is none because earth is stationary and flat.