The combustion of glucose, C6 H12 O6 (s), produces carbon dioxide, CO2 (g), and water, H2 O(g), according to the equation below. Upper C subscript 6 upper H subscript 12 upper O subscript 6 (s) plus 6 upper O subscript 2 (g) right arrow 6 upper C upper O subscript 2 (g) plus 6 upper H subscript 2 upper O (l).

The enthalpy of the reaction is –2,840 kJ. What is the heat of combustion, per mole, of glucose?
–2,840 kJ/mol
–473.3 kJ/mol
473.3 kJ/mol
2,840 kJ/mol

can you attach a picture of the lettuce? : )

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.