A curium-245 nucleus is hit with a neutron and changes as shown by the equation. Complete the equation by filling in the missing parts. 52 54 138 140 142 Xe Te Ce

The question is incomplete, the complete question is:

A curium-245 nucleus is hit with a neutron and changes as shown by the equation. Complete the equation by filling in the missing parts.

The complete equation formed is

Explanation:

The general representation of an isotope is given as:

[rex]_Z^A\textrm{X}[/tex]

where,

A is the mass number, Z is the atomic number and X is the symbol of the element

In a nuclear reaction, total atomic number and total mass number on either side of the reaction remains the same

For the given chemical reaction:

On the reactant side:

Total atomic number = [96 + 0] = 96

Total mass number = [245 + 1] = 246

On the product side:

Total atomic number = [42 + r + 0] = 42 + r

Total mass number = [103 + q + 3] = 106 + q

Calculating for 'r' and 'q', we get:

Thus, the missing isotope is

Hence, the complete equation formed is

28528289 29823282 8298232 39858