Help pls I will give brainliest In the following reaction, oxygen is the excess reactant.
SiCl4+O2=SiO2+Cl2
The table shows an experiment record for the above reaction
Trial 1 :starting amount of SiCl4 150g starting amount of O2 200g actual yield of SiO2 49.2g
Trial 2: starting amount of SiCl4 75g Starting amount of O2 50g actual yield of SiO2 25.2
Calculate the percentage yield for SiO2 for trial 1 also determine the leftover reactant for the trial show your work
Based on the percentage yield in trial 2 explain what ratio of reactants is more effective for the given reaction