You HAVE 1L of 2.0 mol/L HCI. You want to dilute the solution to a concentration of 0.1 mol/L. What volume of the new solution (V2)? 0.05 L

O 20L

0.2 L

M₁ = 2.0 mol/L

V₁ = 1 L

M₂ = 0.1 mol/L

V₂

M₁V₁ = M₂V₂

V₂ = M₁V₁ / M₂

V₂ = (2.0 mol/L)(1 L) / (0.1 L)

V₂ = 20 L

Therefore, the volume of the new solution will be 20 L.

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M₁V₁ = M₂V₂

V₂ = M₁V₁ / M₂

V₂ = (2.0 mol/L)(1 L) / (0.1 L)

V₂ = 20 L

THE BEST ANSWER IS

O 20L