Volumes of 0.18M copper (II) sulfate, and water. 6.5ml 0.18M CuSO4

4.0ml H20

This is my chemistry finals, I need help immediately!

See explanation

Explanation:

Number of moles of Copper sulphate = 0.18 M × 6.5/1000= 1.17 × 10^-3 moles of CuSO4

From;

number of moles = mass/molar mass

Molar mass of copper II sulphate = 160g/mol

1.17 × 10^-3 moles = mass/160g/mol

Mass = 1.17 × 10^-3 moles ×160

Mass = 0.187 g

If 1 mole contains 6.02 × 10^23 molecules

1.17 × 10^-3 moles contains 1.17 × 10^-3 moles × 6.02 × 10^23/1 = 7 × 10^20 molecules

From;

C1 V1=C2 V2

0.18 × 6.5 =C2 × 10.5

C2 = 0.18 × 6.5/10.5

C2=0.11 M

CuSO4(aq) + 2NaOH(aq) > Cu(OH)2(s) + Na2SO4(aq)

1 mole of CuSO4 yields 1 mole of Cu(OH)2

1.17 × 10^-3 moles of CuSO4 yields 1.17 × 10^-3 moles of Cu(OH)2

Mass of Cu(OH)2 = 1.17 × 10^-3 moles × 98g/mol= 0.11g of Cu(OH)2

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?