For the following reaction: 4C2H3Cl + 702 → 8CO + 6H20 + 2Cl2 If the reaction of 57.8 grams of O2 produces 36.5 grams of CO, what is the percent yield?​

Explanation:

Hello there!

In this case, according to the given chemical reaction:

It turns out possible for us to realize about the 7:8 mole ratio of O2 to CO, and therefore, the theoretical yield of the latter is calculated via stoichiometry:

Finally, the percent yield is calculated by dividing the actual yield, 36.5 g by the just computed theoretical one:

Regards!

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.