A stock solution of calcium sulfate, CaSO4 has a concentration of 3.00 M. The volume of this solution is 150 mL. What volume of a 1.25 M solution could be made from the stock solution?

The volume of stock solution needed is 62.5 mL

Explanation:

A solution consists of solute and solvent. A solute is defined as the component that is present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

To calculate the volume of stock solution needed, the formula used is:

            ....(1)

where,

are the concentration and volume of stock solution.

are the concentration and volume of diluted solution.

We are given:

Putting values in equation 1, we get:

Hence, the volume of stock solution needed is 62.5 mL

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.