Find the boiling point of a solution of 2.00 m solution of sodium chloride, NaCl, in water (kb= 0.512°C, bp= 100.0°C)

Boiling point of the given solution is .

Explanation:

Given: Molality = 2.00 m

Now, equation for dissociation of water is as follows.

As it is giving 2 ions upon dissociation. So, the value of i = 2.

Formula used to calculate change in temperature is as follows.

where,

i = Van't Hoff factor

= molal boiling point elevation constant

m = molality

Substitute the values into above formula as follows.

As the boiling point of water is . Hence, the boiling point of solution will be as follows.

Thus, we can conclude that boiling point of the given solution is .

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.

catya that's not even a b or c