Give the IUPAC name for the following alkyl group, and classify it as primary, secondary, or tertiary. CH3(CH2)9CH2

Give the IUPAC name for the following alkyl group, and classify it as primary, secondary, or tertiary.

CH3(CH2)9CH2

Explanation:

In the given alkyl group there are eleven carbon atoms.

So, the alkyl group name is:

n-undecyl.

Pimary carbon is the one which is attached only one other carbon atom,group.

Secondary carbon is the one which is attached to two carbons.

Thertiary carbon is the one which is attached to three other carbons.

In the given alkyl group,

the primary,secondary alkyl groups are shown below:

There is no tertiary carbon atom in the given molecule.

yes it is balanced